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By admin, June 1, 2010 6:25 am

Physics question, help !!!!!!?

A toy car of mass 800g is attached to a runway with a constant level track with a constant speed by a force of 2N 1.What is the friction toy car? (When a car moves with constant velocity, the resulting = 0N) 2.When strength is increased to 6N, which is i) The action of unbalanced force in that? ii) The acceleration of the toy car? Can you do for me step by step response please.

Ok. This is pretty easy. When the car moves with constant velocity, the acceleration of network, therefore, the net force is zero. Therefore, no there is another force of magnitude 2 N, acting on the car in the opposite direction, which we know is friction. We now know that the friction force is 2 N. Therefore, if the external force is 6 N, the unbalanced force is 6 – 2 (cos of friction is opp. toward the applied force.) = 4 N. Therefore, the acceleration = Force / mass = 4/0.8 = 5 m / s ^ 2

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